If the product of three numbers in GP is 216,and their sum is 21, find the numbers
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a/r,a,ar -----GP
a/r×a×ar=a^3=216
a=6.
a/r+a+ar=21
6+6r+6r^2=21r
2r^2-5r+2=0
2r^2-4r-r+2=0
r=2 or r=1/2
no. are 3,6,and 12 when r=2
no. are 12,6,and 3 when r=1/2
a/r×a×ar=a^3=216
a=6.
a/r+a+ar=21
6+6r+6r^2=21r
2r^2-5r+2=0
2r^2-4r-r+2=0
r=2 or r=1/2
no. are 3,6,and 12 when r=2
no. are 12,6,and 3 when r=1/2
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15
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