if the product of three numbers of an ap is 8 and their sum is-3 find the smallest number
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Step-by-step explanation:
Solution :-
Let the number are x−y,x,x+y
Sum =−3
⇒x−y+3x+x+y=−3
⇒3x=−3
⇒x=−1
Now product =8
⇒(x−y)(x)(x+y)=8
Substituting x=−1
we get (−1−y)(−1)(−1+y)=8
(y
2
−1)=8
⇒y=±3
The no : are −4,−1,2 or 2,−1,−4
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