If the product of two consecutive even integers is 224 , then find the integers .
Answers
Answered by
0
Answer:
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Step-by-step explanation:
Let one integer be x, and the other be (x+2)
x(x+2)=224
x2+2x-224=0
(x+16)(x-14) =0
x=-16 or 14
so x+2 = -14 or 16
So the integers are either 14 and 16 or -14 and -16.
Answered by
2
Answer:
let one integer be x
therefore other integer= x+2
now, according to question,
(X)(X+2)=224
x²+2x-224=0
x²+16x-14x-224=0
x(x+16) -14(x+16)=0
(x-14)(x+16)=0
therefore the even integers are 14 and 16 or -14 and -16
hope this helps
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