if the product of two consecutive natural number is 210 then determine the number.
please anyone solve this by Shri dhra charya formula.
otherwise I will report your answer.Note you will be mark as brain list if your answer is right.
Answers
Let assume that
First natural number = x
Second consecutive natural number = x + 1
According to statement,
The product of two consecutive natural number is 210.
So, its a quadratic equation in x.
On comparing with ax² + bx + c = 0, we have
We know, Shree dhar Acharya formula is given by
So, on substituting the values of a, b, c, we get
So, It means
First natural number is 14
Second natural number is 15
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Additional Information :-
Nature of roots :-
Let us consider a quadratic equation ax² + bx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.
If Discriminant, D > 0, then roots of the equation are real and unequal.
If Discriminant, D = 0, then roots of the equation are real and equal.
If Discriminant, D < 0, then roots of the equation are unreal or complex or imaginary.
Where,
Discriminant, D = b² - 4ac
QUESTION :
- if the product of two consecutive natural number is 210 then determine the number.
GIVEN :
- product of two consecutive natural number is 210
TO FIND :
- determine the number = ?
SOLUTION :
Let two consecutive natural numbers be
x and x + 1
According to question :
x × (x + 1) = 210
⇒x²+x - 210 = 0
Using middle tem splitting method, we get :
x² + 15x - 14 x - 210 = 0
x(x +15) - 14 (x +15) = 0
⇒ (x - 14) (x +15) = 0
⇒x=14, -15
x is a natural number thus can't be negative so,
x = 14
and x + 1 = 14 +1 = 15