If the product of two numbers is 2160 and their HCF is 12 what will be the LCM.With steps.
Answers
Answered by
1
let the 2 numbers be a and b.Then according to question:
a*b = 2160
HCF of a and b = 12
We have a relation:
LCM of a and b = Product of 2 numbers a and b / HCF of a and b
so, LCM = 2160/12 = 180
a*b = 2160
HCF of a and b = 12
We have a relation:
LCM of a and b = Product of 2 numbers a and b / HCF of a and b
so, LCM = 2160/12 = 180
Answered by
1
let the two numbers be x and y
their hcf =h=12
lcm =l
formula is
l*h=x*y
l*12 =2160[given xy =2160]
l =2160/12
l =(2*6*180)/12
after cancellation
lcm =180
their hcf =h=12
lcm =l
formula is
l*h=x*y
l*12 =2160[given xy =2160]
l =2160/12
l =(2*6*180)/12
after cancellation
lcm =180
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