Question

If the product of two of the roots of x3-kx2-3x+4=0 may be -1 then k=​

Answer 1

Answer:

GIVEN,

X³-KX²-3X+4=0

AIPHA.BETA=-1=-B/A

HERE A=1 THEN,B=1

-B/A=-1/1=-1

[THEN K=1]

Answer 2

Given;  the product of two of the roots of x3-kx2-3x+4=0 may be -1

To Find; The value of k

Solution; Let the three roots be α,β and z

Product of first two roots is -1

Product of roots = -d/a=-4

-1**z=-4

z=4

Sum product of roots = c/a

α+β+z=-3

α+β=-7

Sum of roots = -b/a

-7+4=k

Hence the value of k is -3

#SPJ3