if the product of two of the zeroes of the polynomial 2x^3-9x^2-13x-6 is 2 ,then the third zero of the polynomial is
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Answered by
76
Answer:
-3/2
Let the three zeros be alpha , beta and gama.
2x^3 - 9x^2 + 13x -6
a = 2 , b = -9 , c = 13 , d = -6
Now , given ...
The product of two zeros is 2 ,
then , alpha × beta = 2 ---- (1)
by formula
alpha × beta × gama = - d / a
= -6/2 = -3 ---- ( 2 )
Now ,
alpha × beta × gama = -3 ---- from ( 2 )
2 gama = -3 ---- ( from 1 , because we have proved alpha × beta = 2 )
gama = -3/2
Hence the third zero is -3/2 ....
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Answer:
3/2 is the 100 percent correct answer
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