Question

If the product of two rational numbers is -9/10 and one of them is -4/15 , find the other number.​

Answer 1

Answer:

Step-by-step explanation:

X*-4/15= -9/10

X= -9/10*-15/4

X=-27/-8= 27/8

Answer 2

Answer:

Given :-

• The product of two rational numbers is - 9/10 and one of them is - 4/15.

To Find :-

• What is the other number.

Solution :-

Let,

$\mapsto \sf\bold{\purple{Other\: Rational\: Number =\: x}}$

Given :

$\leadsto \bf Product\: of\: two\: rational\: number =\: \dfrac{- 9}{10}$

$\leadsto \bf One\: of\: rational\: number =\: \dfrac{- 4}{15}$

According to the question :

$\implies \sf \dfrac{- 4}{15} \times x =\: \dfrac{- 9}{10}$

$\implies \sf x =\: \dfrac{- 9}{10} \div \dfrac{- 4}{15}$

$\implies \sf x =\: \dfrac{\dfrac{- 9}{10}}{\dfrac{- 4}{15}}$

$\implies \sf x =\: \dfrac{- 9}{10} \times \dfrac{- 15}{4}$

$\implies \sf x =\: \dfrac{- 9 \times (- 15)}{10 \times 4}$

$\implies \sf x =\: \dfrac{\cancel{135}}{\cancel{40}}$

$\implies \sf\bold{\red{x =\: \dfrac{27}{8}}}$

$\sf\boxed{\bold{\pink{\therefore\: The\: other\: rational\: number\: is\: \dfrac{27}{8}\: .}}}$

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EXTRA INFORMATION :-

$\leadsto \bf \dfrac{- 4}{15} \times x =\: \dfrac{- 9}{10}$

By putting x = 27/8 we get,

$\leadsto \bf \dfrac{- 4}{15} \times \dfrac{27}{8} =\: \dfrac{- 9}{10}$

$\leadsto \sf \dfrac{- 4 \times 27}{15 \times 8} =\: \dfrac{- 9}{10}$

$\leadsto \sf \dfrac{- 108}{120} =\: \dfrac{- 9}{10}$

$\leadsto \sf\bold{\blue{\dfrac{- 9}{10} =\: \dfrac{- 9}{10}}}$

$\leadsto \sf\bold{\orange{L.H.S =\: R.H.S}}$

Hence, Verified !