if the product of two zeroes of 2x³+6x²-4x+9 is 3 find the other 0
Answers
Polynomial equation, f(x) = 2x³ +6x² -4x+9
Product of 2 zeroes = pq = 3
To find:
Third zero of the equation = r =?
Solution:
Condition to find zeros of polynomial, f(x) = 0.
f(x) = 2x³ +6x² -4x+9 = 0
Comparing the above equation with ax³ +bx² +cx+d = 0, we get,
a = 2, b = 6, c = -4, d = 9
Now,
pqr = -d/a
3r = -9/2
r = -9/6 = -3/2
r = -1.5
Third zero of the equation = r = -1.5
Answer:
If the product of two zeroes of the polynomial f(x) = 2x³ +6x² -4x+9 is 3, then how do you find its third zero?
Given:
Polynomial equation, f(x) = 2x³ +6x² -4x+9
Product of 2 zeroes = pq = 3
To find:
Third zero of the equation = r =?
Solution:
Condition to find zeros of polynomial, f(x) = 0.
f(x) = 2x³ +6x² -4x+9 = 0
Comparing the above equation with ax³ +bx² +cx+d = 0, we get,
a = 2, b = 6, c = -4, d = 9
Now,
pqr = -d/a
3r = -9/2
r = -9/6 = -3/2
r = -1.5