Question

. If the product of two zeroes of
Polynomial
2 x²+3x²_58-6 is 3, then
find its third zero.​

Answer 1

Answer:

Let α,β,γ zeros of the given polynomial p(x).

It is that product of two zeros of p(x) is 3

ie αβ=3 ________ (1)

Here p(x)=x

3

−6x

2

+11x−6 is of the form ax

3

+bx

2

+cx+d

∴a=1,b=−6,c=11,d=−6

Now, αβγ=

a

−d

⇒αβγ=6

⇒γ=

αβ

6

⇒γ=

3

6

[from (1)]

⇒γ=2

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