Question

if the product of two zeroes of the polynemial p(y)=3x2-x2-3x+1 is -1' then find it's third zero​

Answer 1

Answer:

third zero = 1/3

Step-by-step explanation:

Given P(x)= 3 x^3-x^2-3x+1

Let a,b,c are the three zeros of polynemial

P(x)= 3 x^3-x^2-3x+1

Given the product of two zeroes of the polynemial P(x)= 3 x^3-x^2-3x+1 is -1

ab= -1 ---(1)

therefore abc = -1/3 ---(2)

substituting equation (1) in equation (2)

(-1)c = -1/3

c = 1/3

therefore third zero = 1/3