if the product of two zeroes of the polynomials f(y)=3y^3 - 5y^2 - 11y - 3is -3, then find it's third zero
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Answer:
f(x)=2x3+6x2−4x+9
Let three zeroes be α,β,γ
Product of 3 zeroes=a−d=2−9
Given Product of 2 zeroes =3
or α.β=3
⇒αβγ=2−9⇒3γ=2−9⇒γ=2−3
Third zero is 2−3
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