If the product of zeroes of a polynomial ax2-6x-6 is 4 ,then find value of a also find sum of zeroes of polynomial
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Step-by-step explanation:
here
The first term is, ax2 its coefficient is a .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is -6 .
αβ =c/a.
αβ = 4 .(given).
so,c/a =4
-6/a=4/1
(cross multiplication)
-6×1 = 4×a
4a = -6
a =-6/4
a= -3/2.
we know sum of zeroes (α+β) = -b/a .
-b/a = -(-6)/[ -3/2]
+6×[2/-3].
12/-3
=》-4
therefore (α+β) = -4. & a = -3/2.
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Answer:
ur are right
Step-by-step explanation:
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