If the product of zeroes of ax²-6x-6 is 4, Find the value of a . Hence find the sum of it's zeroes.
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Answer:
We also know that the sum of the roots of a quadratic equation is equal to \[ - \dfrac{b}{a}\] and the product of the roots is equal to \[\dfrac{c}{a}\]. It is given that the product of the roots of the polynomial \[a{x^2} - 6x - 6\] is 4. Hence, the value of a is \[ - \dfrac{3}{2}\].
Answered by
2
Answer:
- Value of a = -3/2 (-1.5)
- Value of the sum of its zeroes is -4
Explanation:
Keep in mind these two formulas :
- Sum of the zeroes - (a+b) = -b/a
- Product of the zeroes - (a*b) = c/a
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