Question

If the product of zeroes of P(x) = axcube-6xsquare+11x - 6 is 4 , then a = (a) 0 (b) 5 (c) 1/6 (d) 6

Answer 1

Answer:

$product \: of \: zeros = \frac{ - d}{a} = \frac{ - ( - 6)}{a} = 4$

$a = \frac{6}{4} = \frac{3}{2}$