Question

if the product of zeroes of the polynomial ax square minius 6x minius 6 is 4 find the value of A

Answer 1

Product of roots=c/a

ATP,

4=-6/a

a=-6/4

=-3/2

=-1.5

Thanks.

Answer 2

$\underline{\bold{Answer:-}}$


Given polynomial :-

$ax {}^{2} - 6x - 6$

On comparing with ax^2 + bx + c , we get

A = a , B = - 6 , C = - 6

Given

Product of zeroes = 4

A / q

Product of zeroes = c / a

$\alpha \beta = \frac{ c}{a} \\ \\ = > 4 = \frac{ - 6}{a} \\ \\ = > 4a = - 6 \\ \\ = > a = \frac{ - 6}{4} \\ \\ = > a = \frac{ - 3}{2} .$



Hence, the value of a = - 3 / 2.




$\textbf{Hope it helps!}$