If the product of Zeroes of the polynomial ax² - 6x-6 is 4. Find the value of 'a'. Find the sum of Zeroes of the polynomial.
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Answer: Sum of zeroes = -4
Step-by-step explanation:
Let quadratic equation as
Product of zeroes = c/a and Sum of zeroes = -b/a
So, compare with ax² - 6x - 6 = 0. b = -6, c = -6
So, -6/a = 4 => a = -3/2
Hence, the sum of zeroes = -b/a = 6/a = 6/(-3/2) = -4
(I hope it will be marked as Brainliest)
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