Question

If the product of zeroes of the polynomial ax2 -6x -6 is 4, find the value of ‘a’. find the sum of zeroes of the polynomial.

Answer 1

Answer:

Multiply both side by a.

a^2.x^2+abx+ac=0

(ax)^2+2×ax×b/2+(b/2)^2-b^2/4+ac=0

(ax+b/2)^2=(b^2–4ac)/4

ax+b/2=+/-{(b^2–4ac)^1/2}/2

ax=-b/2+/-{(b^2–4ac)^1/2}/2

x=[-b+/-(b^2–4ac)^1/2]/2a ,

So the no of zeroes = 2

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