Math, asked by Pralavika9061, 10 months ago

If the product of zeroes of the polynomial f(x) = ax3- 6x2-11x-6 is 4,then a=?

Answers

Answered by LovelyG
16

Answer:

a = 3/2

Step-by-step explanation:

Given Polynomial-

f(x) = ax³ - 6x² - 11x - 6

Product of zeroes = -(Constant term)/coefficient of x³

4 = -(-6)/a

On cross multiplying, we get-

4a = 6

a = 6/4

a = 3/2

Hence, the value of x is 3/2.

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For cubic polynomial, ax³ + bx² + cx + d, following are the rules-

  • Sum of zeroes = -b/a
  • Product of zeroes = c/a
  • Sum of product of zeroes = d/a

Answered by abhinavkumar2006
2

Answer:

a = 3/2

Step-by-step explanation:

Given Polynomial-

f(x) = ax³ - 6x² - 11x - 6

Product of zeroes = -(Constant term)/coefficient of x³

4 = -(-6)/a

On cross multiplying, we get-

4a = 6

a = 6/4

a = 3/2

Hence, the value of x is 3/2

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