Math, asked by sc6026849, 2 months ago

if the product of zeroes of the polynomials ax2-6x-12 is 4 the find the value of a.

Answers

Answered by rinkuchoudhary310414
1

Answer:

Shiva Dixon sioxiweuwh x8ewh8x

Step-by-step explanation:

  • 82vhwixnjev7ud widiud
  • us9ejeie
Answered by SteffiPaul
0

Therefore the value of a is -7/2.

Given:

The quadratic polynomial: ax² - 6x - 14 = 0

The product of the zeroes of the given polynomial = 4

To Find:

The value of a.

Solution:

The given question can be solved very easily as shown below.

Given that,

The quadratic polynomial: ax² - 6x - 14 = 0

The product of the zeroes of the given polynomial = 4

If the quadratic polynomial is in the form: px² + qx + r = 0

Then the sum of zeroes = -q/p

The product of zeroes = r/p

Now the given quadratic polynomial is ax² + (-6x) + (-14) = 0

The product of zeroes = r/p = -14/a = 4

⇒ a = -7/2

Therefore the value of a is -7/2.

#SPJ2

Similar questions