if the product of zeroes of the polynomials ax2-6x-12 is 4 the find the value of a.
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Therefore the value of a is -7/2.
Given:
The quadratic polynomial: ax² - 6x - 14 = 0
The product of the zeroes of the given polynomial = 4
To Find:
The value of a.
Solution:
The given question can be solved very easily as shown below.
Given that,
The quadratic polynomial: ax² - 6x - 14 = 0
The product of the zeroes of the given polynomial = 4
If the quadratic polynomial is in the form: px² + qx + r = 0
Then the sum of zeroes = -q/p
The product of zeroes = r/p
Now the given quadratic polynomial is ax² + (-6x) + (-14) = 0
The product of zeroes = r/p = -14/a = 4
⇒ a = -7/2
Therefore the value of a is -7/2.
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