Question

If the product of zeroes of x² - 3kx + 2 k² - 1 is 7, then the values of k are ----------​

Answer 1

Answer:

2k^2-1=7

K^2=4

K=2 or k=-2

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Here a = 1 , b= -3k and c = 2k² -1

=>Product of zeroes = c/a

=> 7 = (2k² -1)/1

=> 2 k² = 7+1

=> k² = 8/2

=> k² = 4

thus, k= 2 or -2

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