Question

If the product of zeros of ax^2-6x-6 is 4, find the value of

a.hence find the sum of its zeros

Answer 1

Hey ,

Given polynomial =

ax² - 6x - 6

Product of zeros = 4 ( given )

Now , as we know

Product of zeros = c / a

=> -6 / a = 4

=> 4a = -6

=> a = -6 / 4

=> a = -3 / 2

So a = -3/2

Now ,

Sum of zeros = - b / a
= -(-6) / -3 /2

= 6 × (-2) / 3

= 2 × ( -2 )

= -4 .

thanks :)