Question

If the product of zeros of polynomial x2-9x+a is 8 then find a

Answer 1

In quadratic questionsof the form ax^2+bx+c=0,

product of roots=c/a

Therefore,a/1=8

a=8

Therefore,value of a = 8

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Answer 2

The value of a is 8.

Step-by-step explanation:

Given : If the product of zeros of polynomial $x^2-9x+a$ is 8.

To find : The value of a ?

Solution :

The quadratic equation is of form $ax^2+bx+c=0$ with roots $\alpha$ and $\beta$.

The product of roots is $\alpha \beta =\frac{c}{a}$

Here,

Product of roots is $\alpha \beta=8$

a=1,b=-9 and c=a

Substitute,

$8=\frac{a}{1}$

$a=8$

Therefore, the value of a is 8.

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