Math, asked by abhaysikri, 9 months ago

If the product of zeros of the polynomial ax^2 - 6x - 6 is 4, find the value of 'a'​

Answers

Answered by MMgudu
1

Answer:

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Since the product of zeros =c/a,

c=-6 , a=a and product of zeros is given i.e, 4

=>c/a=4

=>-6/a=4

=>-6=4a

=>-6/4=a

=>a=-3/2....(answer)...

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Answered by ayushyadav143
0

Answer:

Given polynomial: a x^{2}-6 x-6ax

2

−6x−6

Product of zeroes of this polynomial = 4.

A polynomial is an expression of more than one or two algebraic term, may be a sum of those terms also.

We know, that the product of zeroes of a polynomial a x^{2}+b x+cax

2

+bx+c can be given by =c/a

Hence, for the polynomial: a x^{2}-6 x-6ax

2

−6x−6 , a = a, b = -6 and c = -6.

Product of zeroes of this polynomial = (-6)/a

4 = -6/a

a = -6/4= -3/2

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