If the product of zeros of the polynomial ax^2 - 6x - 6 is 4, find the value of 'a'
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Answered by
1
Answer:
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Since the product of zeros =c/a,
c=-6 , a=a and product of zeros is given i.e, 4
=>c/a=4
=>-6/a=4
=>-6=4a
=>-6/4=a
=>a=-3/2....(answer)...
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Answered by
0
Answer:
Given polynomial: a x^{2}-6 x-6ax
2
−6x−6
Product of zeroes of this polynomial = 4.
A polynomial is an expression of more than one or two algebraic term, may be a sum of those terms also.
We know, that the product of zeroes of a polynomial a x^{2}+b x+cax
2
+bx+c can be given by =c/a
Hence, for the polynomial: a x^{2}-6 x-6ax
2
−6x−6 , a = a, b = -6 and c = -6.
Product of zeroes of this polynomial = (-6)/a
4 = -6/a
a = -6/4= -3/2
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