Question

If the product of zeros of the polynomial x square - 9 x + a is 8 then the value of a is

Answer 1

Answer :-

a = 8

Given :-

$x^2 -9x + a$

Product of zeroes is = 8

To find :-

The value of a.

Solution:-

Let $\alpha$ and $\beta$ be the zeroes of the polynomial.

A/Q

$\alpha \beta = 8$

We know that the relationship between the product of zeroes and it's coefficient is :-

$\huge \boxed{\alpha \beta = \dfrac{c}{a}}$

Put the given values,

→$8 = \dfrac{a}{1}$

→$a = 8$

hence,

The value of a will be 8.

Answer 2

GIVEN:

Polynomial: x² - 9x + a

Product of zeroes = 8

We know that,

Product of zeroes using coefficients= c/a

From the above polynomial,

c = a and a = 1

=> 8 = c/a

=> 8 = a/1

=> a = 8

Therefore, the value of a is 8.