if the product of zeros of the quadratic polynomial kx^2-3x-6 is 4 then find value of k
Answers
Answered by
7
Given Equation
kx² - 3x - 6
The Product of zeroes of the quadratic Polynomial is 4
To Find
The value of k
Now Take
kx² - 3x - 6
So compare with
ax² + bx + c
We get
a = k , b = -3 and c = - 6
We know that
Product of zeroes = c/a
Product of zeroes = 4 , c = -6 and a = k
Put the value
4= -6/k
k = -6/4
k = -3/2
Answer
k = -3/2
Answered by
76
Answer:
k = -3/2
Solution :
Here ,
The given quadratic polynomial is ;
kx² - 3x - 6
Now ,
Comparing the given quadratic polynomial with the general quadratic polynomial ax² + bx + c , we have ;
a = k
b = -3
c = -6
Also ,
It is given that , the product of zeros of the given quadratic polynomial is 4 .
Thus ,
=> Product of zeros = 4
=> c/a = 4
=> -6/k = 4
=> -6/4 = k
=> k = -3/2
Hence , k = -3/2 .
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