Question

If the product of zeros of the quadratic polynomial $f(x)= x^{2}-4x+k$ is 3, find the value of k.

Answer 1

SOLUTION :

Let α  and β are the zeroes of the quadratic polynomial

Given : the quadratic polynomial : x² - 4x + k and αβ = 3

On comparing with ax² + bx + c,

a = 1 , b= -4 , c= k

Product of the zeroes = constant term/ Coefficient of x²

αβ = c/a  

3 = k/1

3 × 1 = k

k = 3  

Hence, the value of k is 3 .

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Answer 2

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The answer goes here....

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》To find :

Value of $k$ .

》Given :

Polynomial = ${x}^{2}-4x+k$

$\alpha\beta=3$

》Solution :

Let $\alpha$ and $\beta$ be the zeroes of the given polynomial.

Comparing with $a{x}^{2}+bx+c$ we get,

$a=1$

$b=-4$

$c=k$

Now,

$Product\:of\:zeroes=\frac{constant\:term}{coefficient\:of\:{x}^{2}}$

$\alpha\beta=\frac{c}{a}$

$3=\frac{k}{1}$

$k=3$

So, the value of k is 3.

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