Question

If the proton and antiproton come closer to each other how much energy released

Answer 1

It just for calculation but it not experimental proof
The energy released = total energy of proton and anti-proton.


Rest energy of a proton/anti-proton = 938.257 MeV (Mega-electronvolts)


now E = mc^2

2 * 938.257 = 1876.514 MeV ( cause there are 2 particles)


1876.514 * 10^6 = 1876514000 eV (get from MeV to eV

1 eV = 1.60 * 10^-19J (convert to joules using charge of an electron (because we're in electron volts))
So 1876514000 eV = (1876514000 * (1.60 * 10^-19)) J
= 3.00 * 10^-10 J