if the pth term of an A.P. is 1/q and the qth term is 1/p,show that the sum of pq terms is 1/2(pq1)
Answers
Answered by
3
Answer:
Step-by-step explanation:
HI,
SO HERE IS THE ANSWER
Given pth term = 1/q
That is ap = a + (p - 1)d = 1/q
aq + (pq - q)d = 1 --- (1)
Similarly, we get ap + (pq - p)d = 1 --- (2)
From (1) and (2), we get
aq + (pq - q)d = ap + (pq - p)d
aq - ap = d[pq - p - pq + q]
a(q - p) = d(q - p)
Therefore, a = d
Equation (1) becomes,
dq + pqd - dq = 1
d = 1/pq
Hence a = 1/pq
Consider, Spq = (pq/2)[2a + (pq - 1)d]
= (pq/2)[2(1/pq) + (pq - 1)(1/pq)]
= (1/2)[2 + pq - 1]
= (1/2)[pq + 1]
HOPE THIS HELPS YOU
MARK IT AS BRAINLIEST
harshtrisha1:
Is this correct bro?
Similar questions