If the pts A(4,3) and B (2,y ) are lie on the circle with centre O (2,3) find the value of y.
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yes
the points are not end points of diameter
It is passing from it Centre fool
control your language my dear boy. i am not a student
if it passes through centre what is the mid point
Ok I m sorry
But see diameter diveds into two equal radius
So it will be mid point
if it passes through the centre, mid point=(4+2)/2,(3+y)/2.
(3,3+y/2) is not equal to (2,3)
Answered by
6
Radius =v(4-2)^2 +(3-3)^2 =v(4+0)=2
V(2-2)^2 +(3-y)^2 =2
(3-y)^2 =4
3-y=+-(2)
Y=5 or1
thanks for trying but the answer is 3 . thanks anyway .
how y=3?
by finding the distance formula for b&o we get root(y^2-6y
+9)
distance OA=OB.
yes
4=root((x2-x1)^2+(y2-y1)^2)
by finding the distance formula for b&o we get root(y^2-6y+9) then we get y^2 -3y-3y+9 then then by solving them we get y=3.
Yes nice bro u understand
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