If the quadratic eq: 3x+1/x=x+3
is written in standard form, then.
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sorry bro its very difficult
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Answer:
(c)
a = 2, b = -3, c = 1
Step-by-step explanation:
left side of equation
take LCM as x
it can simplified as
- (3x^2 + 1) / x = x + 3
if the denominator of LHS moves to RHS it becomes multiple of x + 3 that is
- x ( x + 3 )
- i.e., ( x^2 + 3x )
- the equation is
- (3x^2 + 1) / x = x^2 + 3x
Now move RHS equation to LHS.
that is
2x^2 - 3x + 1 ( if we move left to right or from right to left the positive become negative and negative become positive.)
now coming to answer compare the above equation with standard form of quadratic equation that is ax^2 + bx + c
ax^2 + bx + c
2x^2 - 3x + 1
so by comparing the coefficients we get the answer.
a = 2 , b = -3 , c = 1.
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