if the quadratic equation 2x^2-kx+9=0 has equal roots, then the value of k is ?
Answers
Answered by
0
Answer:
Step-by-step explanation:
⇒ The given quadratic equation is x
2
−kx+9=0, comparing it with ax
2
+bx+c=0
∴ We get, a=1b=−k,c=9
⇒ It is given that roots are real and distinct.
∴ b
2
−4ac>0
⇒ (−k)
2
−4(1)(9)>0
⇒ k
2
−36>0
⇒ k
2
>36
⇒ k>6 or k<−6
∴ We can see values of k given in question are correct.
Answered by
0
Answer:
x=6√2
Step-by-step explanation:
condition of equal root
D=0
b²-4ac=0
k²-4(2)(9) =0
k²=72
k=√72
k=6√2
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