if the quadratic equation 3 x square - 5 x + 2 k =0 for equal root find the value of k
sairam22082003:
which answer is brainlist
Answers
Answered by
2
ATS
D= 0
we know that D= b^2 -4ac
comparing the given equation with general form
a= 3 , b= -5, c= 2k
D= 25 - 24k
comapring both the values of D
0 = 25 -24k
-25 = -24k
25/24 = k
D= 0
we know that D= b^2 -4ac
comparing the given equation with general form
a= 3 , b= -5, c= 2k
D= 25 - 24k
comapring both the values of D
0 = 25 -24k
-25 = -24k
25/24 = k
Answered by
3
3x square - 5x + 2k =0
comparing eq. with 'ax square + bx + c =0'
a =3, b =5, c = 2k
roots r equal
therefore discriminant = 0
b square - 4ac = 0
(5 ×5) - 4×3×2k = 0
25-24k = 0
25 = 24k
k = 25/24
I hope it will help you
comparing eq. with 'ax square + bx + c =0'
a =3, b =5, c = 2k
roots r equal
therefore discriminant = 0
b square - 4ac = 0
(5 ×5) - 4×3×2k = 0
25-24k = 0
25 = 24k
k = 25/24
I hope it will help you
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