If the quadratic equation 3x^2 + 2x + k = 0 has no real roots, then the value of k cannot be
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Answer:
Here is the answer=>
Step-by-step explanation:
If 3x^2+2x+k have no real roots then.
D<0
So b^2-4ac<0
2^2-4(3)(K) <0
4-12K<0
12k>4
k>4/12
So k>1/3.
So the value of k cannot be less than 1/3 as k>1/3.
HOPE IT HELPS.
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