Question

If the quadratic equation (K+1) xsquare - 2(K+1) x +1=0 have real and equal roots then find the value of k

Answer 1

if the roots are real and equal then
b^2-4ac=0
2(k+1)^2-4(k+1)(1)=0
(2k+2)^2-4k-4=0
4k^2+4+8k-4k-4=0
4k^2+4k=0
4k(k+1)=0
(k+1)=0
k=-1