Question

If the quadratic equation KX² - 2KX + 2 = 0 has equal roots then the value of K is .......​

Answer 1

EXPLANATION.

• GIVEN

if the quadratic equation kx^2 - 2kx + 2 = 0

has equal Roots

TO FIND VALUE OF K.

for equation has real and equal roots

Therefore,

$d = {b}^{2} - 4ac = 0$

kx^2 - 2kx + 2 = 0

D = ( -2k)^2 - 4(k)(2) = 0

4k^2 - 8k = 0

k ( 4k - 8 ) = 0

4k - 8 = 0

k = 2

Therefore,

value of k = 2

SOME RELATED FORMULA.

$1) \: d > 0 = roots \: \: are \: \: real \: \: and \: \: unequal$

$2) \: d = 0 \: \: roots \: \: are \: \: real \: \: and \: \: equal$

$3) \: d < 0 \: \: roots \: \: are \: \: imaginary$

Answer 2

Answer:- dear correct anwer is 2

Step-by-step explanation:

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