If the quadratic equation Kx2-2kx-3=0 has equal roots, then find the value of k
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Answer:
root3
Step-by-step explanation:
b^2-4ac=0
=>(2k)^2-4(1)(-3)= 0
=>4k^2+12=0
=>k^2=-12/4
=>k^2=-3
=>k=root 3
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