If the quadratic equation kx²-2kx-3 = 0 has equal roots , then find the value of k
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2
since the eqn have eual rooys
then b2 -4ac= 0
b= 2k and a= k and c=-3
now, (-2k)²-4*k*-3
4k²+12k =0
k²+3k=0
k(k+3)= 0
k+3= 0
k =-3
then b2 -4ac= 0
b= 2k and a= k and c=-3
now, (-2k)²-4*k*-3
4k²+12k =0
k²+3k=0
k(k+3)= 0
k+3= 0
k =-3
Answered by
2
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Step-by-step explanation:
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InFocus:
why 4k is not=to 0
if k=0 then the equation will be -3 ...thats why
-3=0
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