Question

if the quadratic equation mx2+2x+m=0 has two equal roots, then the value of m is

Answer 1

Heya !!




Mx² + 2x + m = 0


Here,


A = m , B = 2 and C = m





Discriminant ( D ) = 0


B² - 4ac = 0



(2)² - 4m² = 0






4m² = 4



m² = 1



m = √1 = 1

Answer 2

Given:

A quadratic equation mx² + 2x + m = 0 has equal roots.

To Find:

The value of k such that the equation has equal roots is?

Solution:

The given problem can be solved using the concepts of quadratic equations.    

1. The given quadratic equation is mx² + 2x + m = 0.  

2. For an equation to have equal roots the value of the discriminant is 0,  

=> The discriminant of a quadratic equation ax² + b x + c = 0 is given by the formula,  

=> Discriminant ( D ) = $\sqrt{b^2 - 4ac}$ .  

=> For equal roots D = 0.  

3. Substitute the values in the above formula,  

=>  D = 0,  

=> √[2² - 4*m*m] = 0,

=> 4 - 4m² = 0,

=>4 = 4m²,

=> m² = 1,

=> m = +1 (OR) m = -1.

Therefore, the values of m are -1 and +1.