if the quadratic equation (px)square _2root 5px +15=0
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A = 2 and
B= 2√5p
C = 15 so,
equal roots so, b²-4ac= 0
now,
2√5p-4(2)(15)=0.
2√5p= 120
p=120/2√5
p= 60/√5
B= 2√5p
C = 15 so,
equal roots so, b²-4ac= 0
now,
2√5p-4(2)(15)=0.
2√5p= 120
p=120/2√5
p= 60/√5
sonusingh6:
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