Math, asked by vishalldalvi2000, 4 months ago

If the quadratic equation px0^(2)

-3px +9 =0 has two equal roots , then

Find value of P ​

Answers

Answered by AtharvSable
3

Answer:

We know that while finding the root of a quadratic equation

ax

2

+bx+c=0 by quadratic formula x=

2a

−b±

b

2

−4ac

,

if b

2

−4ac>0, then the roots are real and distinct

if b

2

−4ac=0, then the roots are real and equal and

if b

2

−4ac<0, then the roots are imaginary.

Here, the given quadratic equation x

2

−px+9=0 is in the form ax

2

+bx+c=0 where a=1,b=−p and c=9.

It is given that the roots are equal, therefore b

2

−4ac=0 that is:

We have, b

2

−4ac=0

⇒(−p)

2

−(4×1×9)=0

⇒p

2

−36=0

⇒p

2

=36

⇒p=±

36

⇒p=±6

Hence, p=±6

Step-by-step explanation:

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Answered by Ishu6395
2

Answer:

we have:

px² - 3px + 9 = 0

for equal roots,

D = 0

therefore, b²-4ac = 0

9p²-36p=0

p=4

HOPE IT HELPS YOU

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