If the quadratic equation px0^(2)
-3px +9 =0 has two equal roots , then
Find value of P
Answers
Answered by
3
Answer:
We know that while finding the root of a quadratic equation
ax
2
+bx+c=0 by quadratic formula x=
2a
−b±
b
2
−4ac
,
if b
2
−4ac>0, then the roots are real and distinct
if b
2
−4ac=0, then the roots are real and equal and
if b
2
−4ac<0, then the roots are imaginary.
Here, the given quadratic equation x
2
−px+9=0 is in the form ax
2
+bx+c=0 where a=1,b=−p and c=9.
It is given that the roots are equal, therefore b
2
−4ac=0 that is:
We have, b
2
−4ac=0
⇒(−p)
2
−(4×1×9)=0
⇒p
2
−36=0
⇒p
2
=36
⇒p=±
36
⇒p=±6
Hence, p=±6
Step-by-step explanation:
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Answered by
2
Answer:
we have:
px² - 3px + 9 = 0
for equal roots,
D = 0
therefore, b²-4ac = 0
9p²-36p=0
p=4
HOPE IT HELPS YOU
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