If the quadratic equation px2 - 2√5px + 15 = 0 has two equal roots then find the value of p.
Answers
Answered by
1358
Hi ,
Compare px² -2√5 px + 15 = 0 with
ax² + bx + c = 0
a = p , b = -2√5 , c = 15
We know that ,
If the roots of the quadratic equation
are equal , then it's discriminant (D)
equals to zero.
D = 0
b² - 4ac = 0
( -2√5 p )² - 4×p ×15 = 0
20p² - 60p = 0
20p( p - 3)= 0
Therefore ,
20p = 0 or ( p- 3 ) = 0
p = 0 or p = 3
I hope this helps you.
:)
Compare px² -2√5 px + 15 = 0 with
ax² + bx + c = 0
a = p , b = -2√5 , c = 15
We know that ,
If the roots of the quadratic equation
are equal , then it's discriminant (D)
equals to zero.
D = 0
b² - 4ac = 0
( -2√5 p )² - 4×p ×15 = 0
20p² - 60p = 0
20p( p - 3)= 0
Therefore ,
20p = 0 or ( p- 3 ) = 0
p = 0 or p = 3
I hope this helps you.
:)
Answered by
417
Answer:
Use b^2-4ac formula
Step-by-step explanation:
px^2 -2 root 5px + 15 = 0
a=p , b= -2root 5p , c= 15
(-2root5p)^2 - 4xpx15 = 0
20 p^2 - 60 p=0
20p(p - 3 ) =0
p-3=0
P = 3
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