Question

if the quadratic equation
$p {x }^{2} + 2 \sqrt{5} \: px + 15 = 0$
have 2 equal root then find value of p?

Answer 1

$hey \: mate \: here \: is \: your \: answer: \\ we \: are \: given \: d = 0 \\ so \: d = b ^{2} - 4ac \\ 0 = 2 \sqrt{5p} {}^{2} - 4(p)(15) \\ 0 = {20p}^{2} - 4(p)(15) \\ 0 = 20p(p - 30) \\ 0 = p -30 \\ p = 30 \\ \\ hope \: it \: helps \: you. \\ plz \: mark \: this \: answer \: as \: brainliest.$