Question

If the quadratic equation x^2-4x+k=0 has real roots, then find the value of k.

Answer 1

Step-by-step explanation:

Given- x^2-4x+k = 0

on comparing with-ax^2+bx+c=0

Here,a=1 , b=-4 , c=k

It is given that,the equation has real,equal root's--

so, D = 0

b^2-4ac = 0

(-4)^2 - 4×1×k =0

16 - 4k = 0

-4k = -16

k = -16/-4

k = 4

Therefore,the value of k is 4

Answer 2

Answer:

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Step-by-step explanation:

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