Question

If the quadratic equation x²-2x+k=0 has equal root then find the value of k​

Answer 1

Answer:

k=1

Step-by-step explanation:

x²-2x+k=0

a=1, b=(-2), c=k

Discriminant=0

b²-4ac=0

(-2)²-4(1)(k)=0

4-4k=0

(-4k)=(-4)

4k=4

k=4/4

k=1

Therefore, the value of k is 1.