If the quadratic equation x²-4x+k=0 lies equal roots, then find the value of k
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Answered by
2
b^2 - 4 ×a×c =0
(-4)^2 - 4×1×k =0
16 - 4k =0
4k =16
k =4
(-4)^2 - 4×1×k =0
16 - 4k =0
4k =16
k =4
Answered by
1
If the quadratic equation x²-4x+k=0 has equal roots
then b^2 -4ac = 0
(-4)^2 - 4(1)(k) = 0
16 = 4k
k = 4
then b^2 -4ac = 0
(-4)^2 - 4(1)(k) = 0
16 = 4k
k = 4
RJUV:
Hope it helps
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