Question

if the quadratic equation xsq-2x+K=0 has equal roots, then value of K is​

Answer 1

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➡Given here .

↪x² -2x +k = 0.......(1)

[ acc. to que. equation have equal roots. ]

So, Let , Root are p and q

p = q ..............(2)

We know ,

Sum of Rooots = -(coffi. of x)/(coffi. of x²)

↪p+q = -(-2)/1

= 2.

And ,

product of Roots = (constant part )/(coffi. of x²)

↪pq = k...............(3)

by equation (1)

↪p= q , keep in (2)

ww get,

↪p+p = 2

.

↪2p = 2

↪p = 1

Again,

p= 1 , keep (2)

↪ 1+q = 2

↪q = 1

Now, keep value of p and q in (3).

↪1×1 = k

↪K = 1

➡Thus :-

↪Valus of K = 1.

✔Hopes its helps u.