if the quadratic polynomial 3 X square + 7 x + 3 then find the value of one upon alpha + 1 upon beta
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Answer:
rits
Step-by-step explanation:
Given that,
p(x)=5y²-7y+1
a=5, b=-7, c=1
alpha(@) +beta(€)=-b/a
=-(-7)/5=7/5
alpha ×beta=c/a
=1/5
→1/alpha+1/beta={€+@}/@€
€/@€+€/@€
@+€/@€
(7/5)/1/5
7/1
=7
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