Question

If the quadrilateral ABCD is a parallelogram what is the value of x

Answer 1

Hlo friend..

Please see the attached picture...

HOPE IT HELPS YOU..

REGARDS
@sunita

Answer 2

The value of x is 36ᵒ

Given :

ABCD is a parallelogram

$\begin{array}{l}{\angle \mathrm{A}=(3 \mathrm{y})^{\circ}} \\ {\angle \mathrm{B}=(2 \mathrm{y}-5)^{\circ}} \\ {\angle \mathrm{C}=(3 \mathrm{x}+3)^{\circ}}\end{array}$

To find :

The value of x

Solution :  

In a parallelogram, adjacent sides are supplementary

Hence the sum of the angles of two adjacent sides $180^{\circ}$

Hence $\angle A+\angle B=180^{\circ}$

$\begin{array}{l}{(3 y)^{\circ}+(2 y-5)^{\circ}=180^{\circ}} \\ {5 y-5=180} \\ {5 y=185} \\ {y=37}\end{array}$

substitute the value of y in $\angle B$

\$\begin{array}{l}{(2 y-5)^{\circ}=(2(37)-5)^{\circ}=69^{\circ}} \\ {\angle C+\angle B=180^{\circ}} \\ {(3 x+3)^{\circ}+69^{\circ}=180^{\circ}} \\ {3 x+72^{\circ}=180^{\circ}} \\ {3 x=108^{\circ}} \\x=36^{\circ}\end{array}$