If the quotient and remainder were 3y - 5 and 9y + 10, on dividing 3y³ + y² + 2y + 5 and g(y). Find g(y)
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Polynomial ch nahi ata kya yarr
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3Y3+Y2+2Y+5=(aY2+bY+c)(3Y-5)+9Y+19
=3aY3+(3b-5a)Y2+(3c-3b+9)Y-5c+10
Equate coefficient of Y3, Y2, Y, we get
a=1, b=2, and c=1
Hence,
aY2+bY+c=Y2+2Y+1
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